Quickly Proving Diestel's Normal Spanning Tree Criterion

نویسندگان

چکیده

We present two short proofs for Diestel's criterion that a connected graph has normal spanning tree provided it contains no subdivision of countable clique in which every edge been replaced by uncountably many parallel edges.

برای دانلود باید عضویت طلایی داشته باشید

برای دانلود متن کامل این مقاله و بیش از 32 میلیون مقاله دیگر ابتدا ثبت نام کنید

اگر عضو سایت هستید لطفا وارد حساب کاربری خود شوید

منابع مشابه

A Simple Existence Criterion for Normal Spanning Trees

Halin proved in 1978 that there exists a normal spanning tree in every connected graph G that satisfies the following two conditions: (i) G contains no subdivision of a ‘fat’ Kא0 , one in which every edge has been replaced by uncountably many parallel edges; and (ii) G has no Kא0 subgraph. We show that the second condition is unnecessary.

متن کامل

Building Spanning Trees Quickly in Maker-Breaker Games

For a tree T on n vertices, we study the Maker-Breaker game, played on the edge set of the complete graph on n vertices, which Maker wins as soon as the graph she builds contains a copy of T . We prove that if T has bounded maximum degree, then Maker can win this game within n+ 1 moves. Moreover, we prove that Maker can build almost every tree on n vertices in n−1 moves and provide non-trivial ...

متن کامل

Encoding Spanning Trees of Complete Multipartite Graphs Quickly

Deo and Micikevicius recently gave a new bijection for spanning trees of complete bipartite graphs. Their method had advantages of linear running time for encoding and decoding, as well as for computing the diameter, center and radius directly from the encoding without having to construct the tree. In this paper we devise a generalization of Deo and Micikevicius’s method, which also a modificat...

متن کامل

4 Minimum Spanning Tree

This first algorithm is quite simple. (Though this was probably known earlier, its proof can be found in Prof. Indyk’s 1999 paper “Sublinear Time Algorithms for Metric Space Problems”.) Let Dij denote the distance between a pair of points i and j, over m total points. The entries of Dij must satisfy the triangle inequality; additionally the matrix is symmetric. Note that the matrix size (i.e., ...

متن کامل

On spanning tree congestion

We prove that every connected graph G of order n has a spanning tree T such that for every edge e of T the edge-cut defined in G by the vertex sets of the two components of T − e contains at most n 32 many edges which solves a problem posed by Ostrovskii (Minimal congestion trees, Discrete Math. 285 (2004), 219-226.)

متن کامل

ذخیره در منابع من


  با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید

ژورنال

عنوان ژورنال: Electronic Journal of Combinatorics

سال: 2021

ISSN: ['1077-8926', '1097-1440']

DOI: https://doi.org/10.37236/9619